Sunday, 31 July 2011

Using MERGE statement in SQL Server 2008

‘MERGE’ statement is a new feature in SQL Server 2008. It can be used to perform insert, update and delete operation on a destination table simultaneously based on the results of a join with a source table. Well, it sounds like a bit confusing, but let's see an example on how it can help us.

Assume we have following two tables.

  • STUDENT_A
  • STUDENT_B

Both table are identical in structure (Structure does not need to be identical).

STUDENT_A

img_scr_001

 

STUDENT_B

img_scr_002

 

And we have to update the ‘STUDENT_A’ with the details at ‘STUDENT_B’. We need to compare and if student ID’s are matched, ‘A’ table should be updated with the ‘B’ table. And if the ID’s in ‘B’ Table are new then we have to insert those to the ‘A’ table.

img_scr_003

 

So using the ‘MERGE’ statement we can achieve this in one execution.

Syntax:

MERGE  <Target> [AS T]
USING <Source> [AS S]
ON <Condition>
[WHEN MATCHED THEN <Execution>]
[WHEN NOT MATCHED BY TARGET <Execution>]
[WHEN NOT MATCHED BY SOURCE <Execution>]


And to do the above operation use the following code:


MERGE STUDENT_A AS T
USING STUDENT_B AS S
ON T.ID = S.ID
WHEN MATCHED THEN UPDATE SET T.AGE = S.AGE
WHEN NOT MATCHED THEN INSERT (ID, FNAME, LNAME, AGE) VALUES(S.ID,S.FNAME,S.LNAME,S.AGE);



**Please note that semicolon ‘;’ is mandatory.


So after executing the above code, and if you inspect the Table ‘A’, you can see that it’s updated the way we wanted.


img_scr_005



 


And also you can use additional rules other than your condition. To illustrate that, first we insert a record to both the tables.


insert into STUDENT_A 
select 10, 'John','Doe',30

insert into STUDENT_B
select 10, 'John','Doe',30



And using the following code you can remove the record with matches the condition and have the value 10.


MERGE STUDENT_A AS T
USING STUDENT_B AS S
ON T.ID = S.ID
WHEN MATCHED and S.ID < 5 THEN UPDATE SET T.AGE = S.AGE
WHEN MATCHED and S.ID = 10 THEN DELETE
WHEN NOT MATCHED BY TARGET THEN INSERT (ID, FNAME, LNAME, AGE) VALUES(S.ID,S.FNAME,S.LNAME,S.AGE);



And if you inspect the table A, you can see that it has the same following results:


img_scr_005

1 comment:

  1. You explained a tough topic very simply, short and sweeet. Nice work!

    ReplyDelete